A 15 m copper run at 10 A on 12 AWG
- Input
- Copper, single-phase, L = 15 m, I = 10 A, 12 AWG (3.31 mm²), supply 230 V
- Working
- VD = 2 × 15 × 10 × 1.68×10⁻⁸ ÷ (3.31×10⁻⁶) = 1.52 V. As a share of the supply: 1.52 ÷ 230 × 100 = 0.66%, so the load receives about 228.48 V.
- Result
- Drop = 1.52 V (0.66% of 230 V)