KKwikfig.

Voltage Drop Calculator

Estimate voltage drop on a cable run by AWG gauge, length, current and conductor — copper or aluminium, single-phase, DC or three-phase, in volts and percent. Runs entirely in your browser — your numbers never leave this device.

Conductor
System
Voltage drop
1.52 V
0.66% of 230 V — load receives about 228.48 V
Drop
1.52 V
Drop %
0.66%
At load
228.48 V
Area
3.31 mm²
Drop for this same run, by gauge
Gauge (AWG)Area (mm²)Drop (V)Drop (%)
142.082.421.05
123.311.520.66
105.260.960.42
88.370.60.26
613.30.380.16
421.20.240.10
326.70.190.08
233.60.150.07
142.40.120.05
1/053.50.090.04
2/067.40.070.03
3/0850.060.03
4/0107.20.050.02

This is a resistive sizing estimate using resistivity at 20 °C — it omits reactance, temperature rise and terminations, and it is not a code-compliance check. Verify final sizing against your local electrical code and the cable manufacturer's data.

How it works

Single-phase / DC (2-wire): VD = 2 × L × I × ρ ÷ A | Three-phase: VD = √3 × L × I × ρ ÷ A | ρ copper = 1.68×10⁻⁸ Ω·m, aluminium = 2.82×10⁻⁸ Ω·m at 20 °C; L = one-way length (m), A = area (m²)
Conductor resistivity and AWG areas used by this calculator
ItemValue
Copper resistivity (20 °C)1.68×10⁻⁸ Ω·m
Aluminium resistivity (20 °C)2.82×10⁻⁸ Ω·m
14 AWG2.08 mm²
12 AWG3.31 mm²
10 AWG5.26 mm²
8 AWG8.37 mm²
6 AWG13.3 mm²
4 AWG21.2 mm²
3 AWG26.7 mm²
2 AWG33.6 mm²
1 AWG42.4 mm²
1/0 AWG53.5 mm²
2/0 AWG67.4 mm²
3/0 AWG85.0 mm²
4/0 AWG107.2 mm²

Every conductor resists the current through it, so a cable run is a resistor in series with the load and some of the supply voltage is spent along the wire instead of at the load. The resistance of the run is ρ × length ÷ area, where ρ is the conductor's resistivity — 1.68×10⁻⁸ Ω·m for copper and 2.82×10⁻⁸ Ω·m for aluminium at 20 °C. A two-wire circuit pays that resistance twice (out and back), giving VD = 2·L·I·ρ/A; a balanced three-phase circuit replaces the factor 2 with √3. Enter the one-way length, the current and the gauge, and the drop comes back in volts, as a percentage of your supply, and side by side for every AWG gauge on the same run so the effect of going one size up is visible.

Read the result as a sizing estimate, not a verdict. This calculation is purely resistive: it omits cable reactance (which matters on large conductors), the rise in resistivity as a loaded cable warms up, and termination and joint resistance, all of which push the real drop a little higher. Electrical codes set their own drop limits and conductor rules that differ by country and installation type, and nothing on this page is a code-compliance check — use the estimate to shortlist a gauge, then verify the final design against your local code and the cable manufacturer's data.

Worked examples

A 15 m copper run at 10 A on 12 AWG

Input
Copper, single-phase, L = 15 m, I = 10 A, 12 AWG (3.31 mm²), supply 230 V
Working
VD = 2 × 15 × 10 × 1.68×10⁻⁸ ÷ (3.31×10⁻⁶) = 1.52 V. As a share of the supply: 1.52 ÷ 230 × 100 = 0.66%, so the load receives about 228.48 V.
Result
Drop = 1.52 V (0.66% of 230 V)

The same run on thinner 14 AWG

Input
Copper, single-phase, L = 10 m, I = 10 A, 14 AWG (2.08 mm²)
Working
VD = 2 × 10 × 10 × 1.68×10⁻⁸ ÷ (2.08×10⁻⁶) = 1.62 V — the gauge table on the calculator shows this shortening fast as the gauge grows: 1.02 V on 12 AWG and 0.64 V on 10 AWG for the identical run.
Result
Drop = 1.62 V on 14 AWG

Three-phase aluminium run

Input
Aluminium, three-phase, L = 30 m, I = 20 A, 10 AWG (5.26 mm²), supply 400 V
Working
VD = √3 × 30 × 20 × 2.82×10⁻⁸ ÷ (5.26×10⁻⁶) = 5.57 V, which is 5.57 ÷ 400 × 100 = 1.39% of the 400 V supply.
Result
Drop = 5.57 V (1.39% of 400 V)

Frequently asked questions

Why does the length count twice on single-phase but not three-phase?

A single-phase or DC load is fed by two wires and the current travels the full run length in each of them, so the drop is 2 × L × I × ρ/A. A balanced three-phase load shares its return between the three phases, and the line-to-line drop works out to √3 × L × I × ρ/A instead — the same resistivity maths with a different circuit factor.

What voltage drop is acceptable?

That is set by your electrical code and by what the load tolerates, not by physics — many codes recommend keeping branch-circuit drop around 3% and total drop around 5% as design guidance, but the binding figure is the one in the code that governs your installation. This page is an estimate to design against those limits, not a compliance check.

Why is aluminium's drop higher than copper's?

Because aluminium's resistivity is higher: 2.82×10⁻⁸ Ω·m against copper's 1.68×10⁻⁸ at 20 °C, a ratio of about 1.68. An aluminium run needs roughly one to two AWG sizes larger than a copper run to land at the same drop — compare both in the gauge table rather than swapping like for like.

Does cable temperature change the result?

Yes — resistivity rises as a conductor warms, roughly 0.4% per °C for copper, so a heavily loaded cable running hot drops more than the 20 °C figure shown here. That is one reason this is an estimate: compare the result against your limit with some margin rather than to the last decimal.

Should I enter the one-way length or there-and-back?

The one-way length — the distance from the supply to the load. The factor 2 in the single-phase formula already accounts for the return conductor, so entering the round trip as well would double-count it and overstate the drop.

Related tools

More in Electrical Calculators · Browse all tools